MATH SOLVE

2 months ago

Q:
# PLS HELP I WILL MARK BRAINLIEST

Accepted Solution

A:

2.1 Subtracting a whole from a fractionRewrite the whole as a fraction using 5 as the denominator : 32 32 β’ 5 32 = ββ = ββββββ 1 5 Equivalent fraction : The fraction thus generated looks different but has the same value as the wholeCommon denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator2.2 Adding up the two equivalent fractionsAdd the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: 32x - (32 β’ 5) 32x - 160 ββββββββββββββ = βββββββββ 5 5 3.1 Pull out like factors : 32x - 160 = 32 β’ (x - 5) 32 β’ (x - 5) ββββββββββββ = 0 5 4.1 When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.Here's how: 32β’(x-5) ββββββββ β’ 5 = 0 β’ 5 5 Now, on the left hand side, the 5 cancels out the denominator, while, on the right hand side, zero times anything is still zero.The equation now takes the shape : 32 β’ (x-5) = 0Equations which are never true: 4.2 Solve : 32 = 0This equation has no solution.A a non-zero constant never equals zero.Solving a Single Variable Equation: 4.3 Solve : x-5 = 0 Add 5 to both sides of the equation : x = 5